How to echo exactly what I want in the source code?

UI.Vision RPA HowTo
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1

Dear UI Vision community,

I’m having this question. For example: If I have a source code and this is what it looks like:

<html url="https://www.google.com" </html>

When I do this:

sourceExtract | <html*</html> | i
echo | ${i} | green

it does echo all the thing, which is <html url="https://www.google.com" </html>

I only want to echo https://www.google.com, what should I modify, or what command should I add?

Thank you guys.

2

I think you need regex

3

I thought about regex, too. But I don’t know how to write the command right. Could you please help me to write it exactly right for this case?

4

storeAttribute | xpath=//html@url | Link
echo | ${Link} | green