Hello,
I’ve a website with 100 link one by one
link1
link2
link3
how can I open each one by one?
Thank yu
Hello,
I’ve a website with 100 link one by one
link1
link2
link3
how can I open each one by one?
Thank yu
Click on a home page link (if it exists)
Use this Javascript with execute script: executescript | return window.history.back(-1);
in this case it will be moved back, to previus, but how then select next link?
Open - Main URL
It has Link1, Link2… Link100
I need to open Link1, go back to Main URL
I need to open Link2, go back to Main URL
…
I need to open Link3, go back to Main URL
Put urls in a csv and open it with open command it’s simple
Hm, I have website with URL like www.main.url
Then I have a category - www.main.url/category1
Then I have a list of links in this category
Then I have category2, and etc.
So, the logic is followin:
I have fiund, that this xPATH //div[@id=‘main_div’]//tr
is for each link, so , open www.main.url/category1
cick //div[@id=‘main_div’]//tr, then go back
click next //div[@id=‘main_div’]//tr, ten go back
click next next //div[@id=‘main_div’]//tr, then go back
Save all url in csc and open it it’s very simple macro
i have 100 link, solution is to safe all 100 links?
Well, im trying to explain again
I have an starting url, - www.my.url/
It has 100 links like
link1, link2, link3 with different slug, so 1st link can be www.my.url/abce, second link can be www.my.url./1349-fdsj and etc
So, what I need, is
I cannot paste to csv file all my 100 links or, on another page it is 8.241 links
You can use an array to save all link and after you can open it
Csv is the best and simply solution